20x^2+32x=-48

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Solution for 20x^2+32x=-48 equation: 



20x^2+32x=-48

We move all terms to the left:

20x^2+32x-(-48)=0

We add all the numbers together, and all the variables

20x^2+32x+48=0

a = 20; b = 32; c = +48;
Δ = b2-4ac
Δ = 322-4·20·48
Δ = -2816
Delta is less than zero, so there is no solution for the equation

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